Directions for correlation and regression for example #1 in class on the TI30XII
1. After turning on, go to EXIT STAT (2nd STATVAR) to clear old work. (It will either clear it or give you an error if it was empty).
2. Go to STAT (2nd DATA)
3. Select 2-VAR (Recall, earlier in the semester when we were doing standard deviations that we selected 1-VAR).
4.
Go to DATA and input
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(Recall x= number of inches of snow per month, y=monthly snowplow bill)
5. Go to STATVAR. Scroll through to see mans, standard deviations, and summations for both x and y. At the end is a (the slope of the regression line, known as b1 in our book), b (the y-intercept in the regression line (b0 in our book), and r (the correlation coefficient).
6. Go to EXIT STAT (2nd STATVAR) to clear your work before doing another example or before returning one of my calculators.
Results for Ex #1:
Calculator reads:
26
=
95
=
244
=
3325
=
900
a =
4.107
b =
-3.929
r=correlation=.9972
Conclusions:
So the correlation is strongly positive at r =0.9972
The linear regression line is
4.107x
– 3.929
Interpretation:
y-intercept: If we get no snow, my monthly bill is -$3.93
slope: For every inch of snow, my bill goes up $4.11.
Calculation formula for Correlation
(page 180 in text-- add this to your formula sheet)
r =
Example #1
Predictor: x= hours of sleep
Response Variable: y= typing speed
x y xy
8 30
6 20
12 45
=
=
=
=
r =

Regression
The equation of the least-squares regression line is given by
=
![]()
Where
or b1=
is
the slope of the regression line
and
is
the y-intercept of the regression line
1. sx is the standard deviation of x. Likewise sy is the standard deviation of y.
2.
were
already calculated in the correlation example.
3.
(for
example on the TI30XII)
4.
(for
example on the TI30XII)
Example #1
b=

=
=